Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (2024)

Class 9: Maths Chapter 6.1 solutions. Complete Class 9 Maths Chapter 6.1 Notes.

Contents

  • 1 Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning
  • 2 Download PDF
  • 3 Chapterwise Maharashtra Board Solutions Class 9 Maths :
  • 4 FAQs
  • 5 About Maharashtra State Board (MSBSHSE)
    • 5.1 Related

Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning

Maharashtra Board 9th Maths Chapter 6.1, Class 9 Maths Chapter 6.1 solutions

Question 1.
Alka spends 90% of the money that she receives every month, and saves ₹ 120. How much money does she get monthly?
Solution:

Let Alka’s monthly income be ₹ x.
Alka spends 90% of the money that she receives every month.
∴ Amount spent by Alka = 90% of x
= 90100 × x = 0.9x 100
Now, Savings = Income – Expenditure
∴ 120 = x – 0.9x
∴120 = 0.1 x
∴ x=1200.1=120×100.1×10
∴ x = 1200
Alka gets ₹ 1200 monthly.

Question 2.
Sumit borrowed a capital of ₹ 50,000 to start his food products business. In the first year he suffered a loss of 20%. He invested the remaining capital in a new sweets business and made a profit of 5%. How much was his profit or loss computed on his original capital ?
Solution:

Original capital borrowed by Sumit = ₹ 50000
Sumit suffered a loss of 20% in his food products business.
∴ Loss suffered in the first year = 20% of 50000
= 20100 × 50000
= ₹10000
Remaining capital = Original capital – loss suffered = 50000- 10000
= ₹ 40000
Sumit invested the remaining capital i.e. ₹ 40,000 in a new sweets business. He made a profit of 5%.
Profit in sweets business = 5% of 40000
= 5100 x 40000 100
= ₹ 2000
New capital with Sumit after the profit in new sweets business = 40000 + 2000 = ₹42000
Since, the new capital is less than the original capital, we can conclude that Sumit suffered a loss.
Total loss on original capital = Original capital – New capital
= 50000 – 42000 = ₹ 8000
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (1)
∴ Sumit suffered a loss of 16% on the original capital.

Question 3.
Nikhil spent 5% of his monthly income on his children’s education, invested 14% in shares, deposited 3% in a bank and used 40% for his daily expenses. He was left with a balance of ₹ 19,000. What was his income that month?
Solution:

Let the monthly income of Nikhil be ₹ x.
Nikhil invested 14% in shares and deposited 3% in a bank.
∴ Total investment = (14% + 3%) of x
= 17% of x
= 17100 × x
= 0.1 7 x
Nikhil spent 5% on his children’s education and used 40% for his daily expenses.

∴ Total expenditure = (5% + 40%) of x
= 45% of x
= 45100 × x
= 0.45x
Amount left with Nikhil = 19,000
Amount left with Nikhil = Income – (Total investment + Total expenditure)
∴ 19000 = x – (0.17x + 0.45x)
∴ 19000 = x – 0.62x ,
∴ 19000 = 0.38x
∴ x=190000.38=19000×1000.38×100=190000038
= 50000
∴ The monthly income of Nikhil is ₹ 50000.

Question 4.
Mr. Sayyad kept ₹ 40,000 in a bank at 8% compound interest for 2 years. Mr. Fernandes invested ₹ 1,20,000 in a mutual fund for 2 years. After 2 years, Mr. Fernandes got ₹ 1,92,000. Whose investment turned out to be more profitable?
Solution:

Mr. Sayyad:
Mr. Sayyad kept ₹ 40,000 in a bank at 8% compound interest for 2 years P = ₹ 40000, R = 8%, n = 2 years
∴ Compound interest (I)
= Amount (A) – Principal (P)
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (2)
= 40000 [(1 +0.08)2 – 1]
= 40000 [(1.08)2 – 1]
= 40000(1.1664 – 1)
= 40000 (0.1664)
= ₹ 6656
∴ Mr. Sayyad’s percentage of profit Interest
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (3)

Mr. Fernandes:
Amount invested by Mr. Fernandes in mutual fund = ₹ 120000
Amount received by Mr. Fernandes after 2 years = ₹ 192000
∴ Profit earned by Mr. Fernandes
= Amount received – Amount invested
= 192000- 120000
= ₹72000
∴ Mr. Fernandes percentage of profit Profit earned
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (4)
= 60%
From (i) and (ii),
Investment of Mr. Fernandes turned out to be more profitable.

Question 5.
Sameera spent 90% of her income and donated 3% for socially useful causes. If she was left with ₹ 1750 at the end of the month, what was her actual income ?
Solution:

Let the actual income of Sameera be ₹ x.
Sameera spent 90% of her income and donated 3%.
∴ Sameera’s total expenditure
= (3% + 90%) of x
= 93% of x
= 93100 × x
= 0.93x
Now, Savings = Income – Expenditure
∴ 1750 = x-0.93x
∴ 1750 = 0.07x
x=17500.07=1750×1000.07×100=1750007=25000
∴ The actual income of Sameera is ₹ 25000.

Question 1.
Amita invested some part of ₹ 35000 at 4% and the rest at 5% interest for one year. Altogether her gain was ₹ 1530. Find out the amounts she had invested at the two different rates. Write your answer in words. (Textbook pg. no. 97)
Solution:

Let the amount invested at the rate of 4% and 5% be ₹ x and ₹ y respectively.
According to the first condition, total amount invested = ₹ 35000
∴ x + y = 35000 …(i)
According to the second condition,
total interest received at 4% and 5% is ₹ 1530.
∴ 4 % of x + 5 % of y = 1530
∴ 4100 x x + 5100 x y = 1530
∴ 4x + 5y = 153000 …(ii)
Multiplying equation (i) by 4, we get
4x + 4y = 140000 …(iii)
Subtracting equation (iii) from (ii),
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (5)
Substituting y = 13000 in equation (i),
x + 13000 = 35000
∴ x = 35000 – 13000 = 22000
Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (6)
∴ Amita invested ₹ 22000 at the rate of 4% and ₹ 13000 at the rate of 5%.

Download PDF

Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning

Download PDF: Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning PDF

Chapterwise Maharashtra Board Solutions Class 9 Maths :

Part 1

  • Chapter 1.1- Sets
  • Chapter 1.2- Sets
  • Chapter 1.3- Sets
  • Chapter 1.4- Sets
  • Chapter 2.1- Real Numbers
  • Chapter 2.2- Real Numbers
  • Chapter 2.3- Real Numbers
  • Chapter 2.4- Real Numbers
  • Chapter 2.5- Real Numbers
  • Chapter 3.1- Polynomials
  • Chapter 3.2- Polynomials
  • Chapter 3.3- Polynomials
  • Chapter 3.4- Polynomials
  • Chapter 3.5- Polynomials
  • Chapter 3.6- Polynomials
  • Chapter 4.1- Ratio and Proportion
  • Chapter 4.2- Ratio and Proportion
  • Chapter 4.3- Ratio and Proportion
  • Chapter 4.4- Ratio and Proportion
  • Chapter 4.5- Ratio and Proportion
  • Chapter 5.1- Linear Equations in Two Variables
  • Chapter 5.2- Linear Equations in Two Variables
  • Chapter 6.1- Financial Planning
  • Chapter 6.2- Financial Planning
  • Chapter 7.1- Statistics
  • Chapter 7.2- Statistics
  • Chapter 7.3- Statistics
  • Chapter 7.4- Statistics
  • Chapter 7.5- Statistics

FAQs

Where do I get the Maharashtra State Board Books PDF For free download?

You can download the Maharashtra State Board Books from the eBalbharti official website, i.e. cart.ebalbharati.in or from this article.

How to Download Maharashtra State Board Books?

Students can get the Maharashtra Books for primary, secondary, and senior secondary classes from here. You can view or download theMaharashtra State Board Booksfrom this page or from the official website for free of cost. Students can follow the detailed steps below to visit the official website and download the e-books for all subjects or a specific subject in different mediums.
Step 1:Visit the official websiteebalbharati.in
Step 2:On the top of the screen, select “Download PDF textbooks”
Step 3:From the “Classes”section, select your class.
Step 4:From “Medium”, select the medium suitable to you.
Step 5:All Maharashtra board books for your class will now be displayed on the right side.
Step 6:Click on the “Download”option to download the PDF book.

Who developed the Maharashtra State board books?

As of now, the MSCERT and Balbharti are responsible for the syllabus and textbooks of Classes 1 to 8, while Classes 9 and 10 are under the Maharashtra State Board of Secondary and Higher Secondary Education (MSBSHSE).

How many state boards are there in Maharashtra?

The Maharashtra State Board of Secondary & Higher Secondary Education, conducts the HSC and SSC Examinations in the state of Maharashtra through itsnineDivisional Boards located at Pune, Mumbai, Aurangabad, Nasik, Kolhapur, Amravati, Latur, Nagpur and Ratnagiri.

About Maharashtra State Board (MSBSHSE)

The Maharashtra State Board of Secondary and Higher Secondary Education or MSBSHSE (Marathi: महाराष्ट्र राज्य माध्यमिक आणि उच्च माध्यमिक शिक्षण मंडळ), is anautonomous and statutory body established in 1965. The board was amended in the year 1977 under the provisions of the Maharashtra Act No. 41 of 1965.

The Maharashtra State Board of Secondary & Higher Secondary Education (MSBSHSE), Pune is an independent body of the Maharashtra Government. There are more than 1.4 million students that appear in the examination every year. The Maha State Board conducts the board examination twice a year. This board conducts the examination for SSC and HSC.

The Maharashtra government established the Maharashtra State Bureau of Textbook Production and Curriculum Research, also commonly referred to as Ebalbharati, in 1967 to take up the responsibility of providing quality textbooks to students from all classes studying under the Maharashtra State Board. MSBHSE prepares and updates the curriculum to provide holistic development for students. It is designed to tackle the difficulty in understanding the concepts with simple language with simple illustrations. Every year around 10 lakh students are enrolled in schools that are affiliated with the Maharashtra State Board.

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Maharashtra Board Solutions Class 9-Maths (Part 1): Chapter 6.1- Financial Planning (2024)
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